std::rotate_copy
From cppreference.com
Defined in header <algorithm>
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(1) | ||
template< class ForwardIt, class OutputIt > OutputIt rotate_copy( ForwardIt first, ForwardIt n_first, |
(until C++20) | |
template< class ForwardIt, class OutputIt > constexpr OutputIt rotate_copy( ForwardIt first, ForwardIt n_first, |
(since C++20) | |
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2 > ForwardIt2 rotate_copy( ExecutionPolicy&& policy, ForwardIt1 first, ForwardIt1 n_first, |
(2) | (since C++17) |
1) Copies the elements from the range
[first, last)
, to another range beginning at d_first
in such a way, that the element n_first
becomes the first element of the new range and n_first - 1
becomes the last element. 2) Same as (1), but executed according to
policy
. This overload only participates in overload resolution if std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is trueParameters
first, last | - | the range of elements to copy |
n_first | - | an iterator to an element in [first, last) that should appear at the beginning of the new range
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d_first | - | beginning of the destination range |
policy | - | the execution policy to use. See execution policy for details. |
Type requirements | ||
-ForwardIt, ForwardIt1, ForwardIt2 must meet the requirements of LegacyForwardIterator.
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-OutputIt must meet the requirements of LegacyOutputIterator.
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Return value
Output iterator to the element past the last element copied.
Exceptions
The overload with a template parameter named ExecutionPolicy
reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation
See also the implementations in libstdc++ and libc++.
Example
Run this code
#include <algorithm> #include <vector> #include <iostream> int main() { std::vector<int> src = {1, 2, 3, 4, 5}; auto pivot = std::find(src.begin(), src.end(), 3); std::vector<int> dest(src.size()); std::rotate_copy(src.begin(), pivot, src.end(), dest.begin()); for (const auto &i : dest) { std::cout << i << ' '; } std::cout << '\n'; }
Output:
3 4 5 1 2
Complexity
linear in the distance between first
and last
See also
rotates the order of elements in a range (function template) |