std::find_end
Defined in header <algorithm>
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(1) | ||
template< class ForwardIt1, class ForwardIt2 > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, |
(until C++20) | |
template< class ForwardIt1, class ForwardIt2 > constexpr ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, |
(since C++20) | |
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2 > ForwardIt1 find_end( ExecutionPolicy&& policy, ForwardIt1 first, ForwardIt1 last, |
(2) | (since C++17) |
(3) | ||
template< class ForwardIt1, class ForwardIt2, class BinaryPredicate > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, |
(until C++20) | |
template< class ForwardIt1, class ForwardIt2, class BinaryPredicate > constexpr ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, |
(since C++20) | |
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2, class BinaryPredicate > ForwardIt1 find_end( ExecutionPolicy&& policy, ForwardIt1 first, ForwardIt1 last, |
(4) | (since C++17) |
Searches for the last occurrence of the sequence [s_first, s_last)
in the range [first, last)
.
operator==
.p
.policy
. These overloads do not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is trueParameters
first, last | - | the range of elements to examine |
s_first, s_last | - | the range of elements to search for |
policy | - | the execution policy to use. See execution policy for details. |
p | - | binary predicate which returns true if the elements should be treated as equal. The signature of the predicate function should be equivalent to the following: bool pred(const Type1 &a, const Type2 &b); While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) |
Type requirements | ||
-ForwardIt1 must meet the requirements of LegacyForwardIterator.
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-ForwardIt2 must meet the requirements of LegacyForwardIterator.
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Return value
Iterator to the beginning of last occurrence of the sequence [s_first, s_last)
in range [first, last)
.
If no such sequence is found, |
(until C++11) |
If |
(since C++11) |
Complexity
Does at most S*(N-S+1)
comparisons where S = distance(s_first, s_last) and N = distance(first, last).
Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation
First version |
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template<class ForwardIt1, class ForwardIt2> ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last) { if (s_first == s_last) return last; ForwardIt1 result = last; while (true) { ForwardIt1 new_result = std::search(first, last, s_first, s_last); if (new_result == last) { break; } else { result = new_result; first = result; ++first; } } return result; } |
Second version |
template<class ForwardIt1, class ForwardIt2, class BinaryPredicate> ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p) { if (s_first == s_last) return last; ForwardIt1 result = last; while (true) { ForwardIt1 new_result = std::search(first, last, s_first, s_last, p); if (new_result == last) { break; } else { result = new_result; first = result; ++first; } } return result; } |
Example
The following code uses find_end()
to search for two different sequences of numbers.
#include <algorithm> #include <iostream> #include <vector> int main() { std::vector<int> v{1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4}; std::vector<int>::iterator result; std::vector<int> t1{1, 2, 3}; result = std::find_end(v.begin(), v.end(), t1.begin(), t1.end()); if (result == v.end()) { std::cout << "sequence not found\n"; } else { std::cout << "last occurrence is at: " << std::distance(v.begin(), result) << "\n"; } std::vector<int> t2{4, 5, 6}; result = std::find_end(v.begin(), v.end(), t2.begin(), t2.end()); if (result == v.end()) { std::cout << "sequence not found\n"; } else { std::cout << "last occurrence is at: " << std::distance(v.begin(), result) << "\n"; } }
Output:
last occurrence is at: 8 sequence not found
See also
searches for a range of elements (function template) | |
returns true if one set is a subset of another (function template) | |
finds the first two adjacent items that are equal (or satisfy a given predicate) (function template) | |
(C++11) |
finds the first element satisfying specific criteria (function template) |
searches for any one of a set of elements (function template) | |
searches a range for a number of consecutive copies of an element (function template) |