C++ named requirements: Erasable
Specifies that an object of the type can be destroyed by a given Allocator.
Requirements
The type T is Erasable from the Container X whose value_type is identical to T if, given
A
|
an allocator type |
m
|
an lvalue of type A
|
p
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the pointer of type T* prepared by the container
|
where X::allocator_type is identical to std::allocator_traits<A>::rebind_alloc<T>,
the following expression is well-formed:
std::allocator_traits<A>::destroy(m, p);
If X is not allocator-aware, the term is defined as if A were std::allocator<T>, except that no allocator object needs to be created, and user-defined specializations of std::allocator are not instantiated.
Notes
All standard library containers require that their element type satisfies Erasable.
With the default allocator, this requirement is equivalent to the validity of p->~T(), which accepts class types with accessible destructors and all scalar types, but rejects array types, function types, reference types, and void.
See Also
| CopyInsertable | |
| MoveInsertable | |
| EmplaceConstructible | |
| Destructible |