std::prev
From cppreference.com
Defined in header <iterator>
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template< class BidirIt > BidirIt prev( |
(since C++11) (until C++17) |
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template< class BidirIt > constexpr BidirIt prev( |
(since C++17) | |
Return the nth predecessor of iterator it.
Parameters
it | - | an iterator |
n | - | number of elements it should be descended |
Type requirements | ||
-BidirIt must meet the requirements of LegacyBidirectionalIterator.
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Return value
The nth predecessor of iterator it.
Complexity
Linear.
However, if BidirIt
additionally meets the requirements of LegacyRandomAccessIterator, complexity is constant.
Possible implementation
template<class BidirIt> BidirIt prev(BidirIt it, typename std::iterator_traits<BidirIt>::difference_type n = 1) { std::advance(it, -n); return it; } |
Notes
Although the expression --c.end() often compiles, it is not guaranteed to do so: c.end() is an rvalue expression, and there is no iterator requirement that specifies that decrement of an rvalue is guaranteed to work. In particular, when iterators are implemented as pointers, --c.end() does not compile, while std::prev(c.end()) does.
Example
Run this code
#include <iostream> #include <iterator> #include <vector> int main() { std::vector<int> v{ 3, 1, 4 }; auto it = v.end(); auto pv = std::prev(it, 2); std::cout << *pv << '\n'; }
Output:
1
See also
(C++11) |
increment an iterator (function template) |
advances an iterator by given distance (function template) |