std::dec, std::hex, std::oct
From cppreference.com
Defined in header <ios>
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std::ios_base& dec( std::ios_base& str ); |
(1) | |
std::ios_base& hex( std::ios_base& str ); |
(2) | |
std::ios_base& oct( std::ios_base& str ); |
(3) | |
Modifies the default numeric base for integer I/O.
1) sets the basefield
of the stream str
to dec
as if by calling str.setf(std::ios_base::dec, std::ios_base::basefield)
2) sets the basefield
of the stream str
to hex
as if by calling str.setf(std::ios_base::hex, std::ios_base::basefield)
3) sets the basefield
of the stream str
to oct
as if by calling str.setf(std::ios_base::oct, std::ios_base::basefield)
This is an I/O manipulator. It may be called with an expression such as out << std::hex for any out
of type std::basic_ostream or with an expression such as in >> std::hex for any in
of type std::basic_istream.
Parameters
str | - | reference to I/O stream |
Return value
str
(reference to the stream after manipulation)
Example
Run this code
#include <iostream> #include <sstream> int main() { std::cout << "The number 42 in octal: " << std::oct << 42 << '\n' << "The number 42 in decimal: " << std::dec << 42 << '\n' << "The number 42 in hex: " << std::hex << 42 << '\n'; int n; std::istringstream("2A") >> std::hex >> n; std::cout << std::dec << "Parsing \"2A\" as hex gives " << n << '\n'; // the output base is sticky until changed std::cout << std::hex << "42 as hex gives " << 42 << " and 21 as hex gives " << 21 << '\n'; }
Output:
The number 42 in octal: 52 The number 42 in decimal: 42 The number 42 in hex: 2a Parsing "2A" as hex gives 42 42 as hex gives 2a and 21 as hex gives 15
See also
changes the base used for integer I/O (function) | |
controls whether prefix is used to indicate numeric base (function) |